a^2x^2-5abx+4b^2=0

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Solution for a^2x^2-5abx+4b^2=0 equation:


Simplifying
a2x2 + -5abx + 4b2 = 0

Reorder the terms:
-5abx + a2x2 + 4b2 = 0

Solving
-5abx + a2x2 + 4b2 = 0

Solving for variable 'a'.

Factor a trinomial.
(ax + -4b)(ax + -1b) = 0

Subproblem 1

Set the factor '(ax + -4b)' equal to zero and attempt to solve: Simplifying ax + -4b = 0 Solving ax + -4b = 0 Move all terms containing a to the left, all other terms to the right. Add '4b' to each side of the equation. ax + -4b + 4b = 0 + 4b Combine like terms: -4b + 4b = 0 ax + 0 = 0 + 4b ax = 0 + 4b Remove the zero: ax = 4b Divide each side by 'x'. a = 4bx-1 Simplifying a = 4bx-1

Subproblem 2

Set the factor '(ax + -1b)' equal to zero and attempt to solve: Simplifying ax + -1b = 0 Solving ax + -1b = 0 Move all terms containing a to the left, all other terms to the right. Add 'b' to each side of the equation. ax + -1b + b = 0 + b Combine like terms: -1b + b = 0 ax + 0 = 0 + b ax = 0 + b Remove the zero: ax = b Divide each side by 'x'. a = bx-1 Simplifying a = bx-1

Solution

a = {4bx-1, bx-1}

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